Math, asked by riyakumariips2704, 21 days ago

find the capacity in litres of a conical vessel with (I) radius 7cm, slant height 25cm. (ii) radius 12cm, slant height 13cm.​

Answers

Answered by akhilkumarnikhil24
2

Answer:

Capacity of a conical vessel is nothing but the volume of the cone.

Volume of a cone of base radius r, and height h = 1/3πr2h

Slant height of the cone, l = √r² + h²

i) Radius of the conical vessel, r = 7cm

Slant height of the conical vessel, l = 25cm

Height of the conical vessel, h = √l² - r²

= √(25)² - (7)²

= √625 - 49

= √576

h = 24 cm

Capacity of the conical vessel = 1/3 πr²h

= 1/3 × 22/7 × 7 cm × 7 cm × 24 cm

= 1232 cm³

= 1232 × (1/1000L) [∵ 1000 cm³ = 1litre]

= 1.232 litres

ii) Height of the conical vessel, h = 7cm

Slant height of the conical vessel, l = 13cm

Radius of the conical vessel, r = √l² - h²

= √(13)² - (12)²

= √169 -144

= √25

r = 5 cm

Capacity of the conical vessel = 1/3πr²h

= 1/3 × 22/7 × 5 cm × 5 cm × 12 cm

= 2200/7 cm³

= 2200/7 × 1/1000 l [∵ 1000 cm³ = 1litre]

= 11/35 litres

Step-by-step explanation:

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Answered by zoyas1498
1

Step-by-step explanation:

From Pythagoras theorem, 

r2+h2=hs2

72+h2=252

⇒h2=576

⇒h=24cm

⇒ Volume=31πr2h

=31π×72×24

=2392πcm3=2000392πl

=1000190πl.

(ii) r2+h2=hs2    [Ref. image 2]

⇒122+r2=132

⇒r2=25

⇒r=5

⇒ Volume=31πr2h

=31π

hope you understand

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