Question

Find the capacity of a closed rectangular cistern whose length is 8 m,breadth 6 m and depth 2.5 m. Also, find the area of the iron sheet required to make the cistern
please answer it fast, it's very urgent

Answer 1

Answer:

Step-by-step explanation:

Capacity of cistern is volume of cistern

i.e l * b * h

Capacity = 8 * 6 * 2.5 = 120m^3

area of iron sheet required = surface area of cistern

surface area of cistern = 2(l * b + b * h + l * h)

                                      =2(8 * 6 + 6 * 2.5 + 8 * 2.5) = 166m^2

area of iron sheet required = 166m^2

If given that topmost surface is open then subtract  l *b from surface area since it won't be used off iron sheet

otherwise above is answer...

Hope it helps :-)

Answer 2

$\Large{ \mathfrak{ \underline{ Question : }}} \\ \\ \textsf {Find the capacity of a closed rectangular } \\ \textsf{cistern whose length is 8 m, breadth 6 m } \\ \textsf{and depth 2.5 m. Also, find the area of the } \\ \textsf{iron sheet requires making the cistern.} \\ \\ \Large{ \mathfrak{ \underline{ Answer : }}} \\ \\ {\underline{\boxed{ \textsf {Capacity of Closed Rectangular Cistern = 120 m} \sf {}^{3} }}} \\ {\underline{\boxed{ \textsf {Area of the iron sheet required = 166} \sf \: {m}^{2} }}} \\ \\ \Large{ \mathfrak{ \underline{ Solution : }}} \\ \\ \sf Length \: of \: Cistern = 8 m \\ \sf Breadth \: of \: Cistern = 6 m \\ \sf Height \: of \: Cistern = 2.5 m \\ \\ \textsf{Therefore, the capacity of the cistern = Volume of the cistern} \\ \\ \sf Volume \: of \: cistern \\ \qquad \sf= l × b × h \\ \qquad \sf = 8 \times 6 \times 2.5 \\ \qquad \sf = 120 \: {m}^{3} \\ \\ \textsf{Area of the iron sheet required = Total surface area of the cistern} \\ \\ \sf ∴Total \: surface \: area \\ \qquad \sf = 2(lb + bh + hl) \\ \qquad \sf = 2 \{(8 × 6) + (6 × 2.5) + (2.5 × 8) \} \\ \qquad \sf = 2(48 + 15 + 20) \\ \qquad \sf = 2 \times 83 \\ \qquad \sf = 166 \: {m}^{2}$