Question

find the capacity of frustrum of cone of radius 4cm and 2cm with height 14cm
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Answer 1

Answer:

radius A =4cm

radius B = 2cm

height = 14cm

Volume of the frustrum:

$= \frac{1}{3 } \times \: \frac{22}{7} \times 14 \times (16 + 4 + 8)$

$= \frac{1}{3} \times 22 \times 2(28)$

$= \frac{1}{3} \times 22 \times 56$

$= \frac{1}{3} \times 1232$

$= 410.66$

Therefore, capacity of frustrum is 410.66cm³.

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