Question

find the capacity of tank
pipe A and B can fill the tank in 10 hour.
pipe B can fill the tank in 18 hour at the rate of 4 galion per minute

Answer 1

Answer:

in 1 minute B fills 4gallons

in 18 hr it can fill the full tank and hence capacity of the tank in= 4*60*18= 4320 gallons

Answer 2

The capacity of the tank is 4320 gallons.

Step-by-step explanation:

Given:

The tank can be filled by Pipe A and Pipe B in 10 hours.

Pipe B can fill the tank in 18 hours at the rate of 4 gallons per minute.

To Find:

The capacity of the tank.

Formula Used:

$S=\frac{V}{T}$      ------------------ formula no.01.

Where    S- speed

               V- capacity of the tank

               T- time is taken by pipe B to fill the tank.

Solution:

As given- pipe B can fill the tank in 18 hours at the rate of 4 gallons per minute.      

S= 4 gallons per minutes= 4x60 gallons /hours = 240 gallons/hours    

T=18 hours

Putting the value of S and T in the formula no.01.

 $240=\frac{V}{18}$

 $V=240\times 18$

     $=4320$ gallons

Thus, the capacity of the tank  is 4320 gallons.