Question

Find the cardinal number of set S = The set of all leap years between 1882 and 1906.

Answer 1

Hey there!

A year which is divisible by 4 is a leap year.

1884 , 1888 , 1892 , 1896 , 1904 are the leap years between 1882 & 1906

1900 is a century year, for it to be a leap year, it needs to be divided by 400 , but it doesn't get divisible.

Number of leap year between 1882 , 1906 = 5

Set S = { 1884 , 1888 , 1892 , 1896 , 1904 }

$\quad \quad \quad \boxed{\boxed{n(S) = 5}}$

Therefore, Cardinal number of the set S is 5

Answer 2

Hi ,

A leap year has 365 days .

S = set of all leap years between

1882 and 1906

S = { 1884,1888,1892,

1896,1904 }

Cardinal number of Set S = n(S)

Number of elements in Set S

n(S) = 5

I hope this helps you.

: )