find the cartesian coordinates of the point whose polar coordinates are ( 3/4 ,135°)
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( -3√2/8 , 3√2/8) is Cartesian coordinates of the point whose polar coordinates are ( 3/4 ,135°)
Given:
- Polar coordinate (3/4 , 135°)
To Find:
- The cartesian coordinates
Solution
- For Polar coordinate (r ,θ ) , cartesian coordinates are given by (rcosθ , rsinθ)
- x = rcosθ , y = rsinθ ( x , y) is cartesian coordinate
Step 1:
Find x coordinate as x = rcosθ and substitute r = 3/4 and θ = 135°
x = (3/4)cos135°
Step 2:
Use cos135° = -1/√2 and calculate value of x
x = (3/4)(-1/√2)
x = -3√2/8
Step 3:
Find y coordinate as y = rsinθ and substitute r = 3/4 and θ = 135°
y = (3/4)sin135°
Step 4:
Use sin135° = 1/√2 and calculate value of y
y = (3/4) (1/√2)
y = 3√2/8
Hence (x , y) is ( -3√2/8 , 3√2/8)
( -3√2/8 , 3√2/8) is Cartesian coordinates of the point whose polar coordinates are ( 3/4 ,135°)
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