Question

Find the cartesian equation of the line which passes through the point (- 2, 4, - 5) and parallel to the line given by $\frac{x+3}{3} = \frac{y-4}{5}=\frac{z+8}{6}$.

Answer 1

$r = ( - 2i + 4j - 5k) + \alpha (3i + 5j + 6k)$