Question

Find the center and radius of circle 2x^2+2y^2-3x-7y+2=0

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

2x2 + 8x + (____) + 2y2 - 12y + (____) = 24

Then divide through by the coefficients of the two squared terms.  You're trying to make this look like the equation for a circle which has the two square binomials set equal to the radius.  Anyway, since both coefficients are 2, simply divide the whole thing by two.

x2 + 4x + (____) + y2 - 6y + (____) = 12

Now look at the x term, 4x.  Take half of the coefficient (4/2 = 2) and square it (which brings us back to 4, coincidentally) and add that to both sides.  Do the same for the Y term.  Write it like this to show clearly what you've done:

x2 + 4x + (4) + y2 - 6y + (9) = 12 + 4 + 9

Now factor your two perfect square trinomials and add up all the loose numbers on the right.

(x + 2)2 + (y - 3)2 = 52  (Turned the 25 into 5-squared for the next step.  You should do this too)

This looks like:

(x - h)2 + (y - k)2 = r2