Find the center and radius of the circle with equation x^2 + y^2 -2x + 4y - 11 = 0
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An equation of the circle with center (h, k) and radius ris
(x - h)² + (y - k)² = r²
Consider, x² + y² + 4y = 0, it can be rewritten
as:
x² + y² + 4y +4= 0+4
implies (x + 0)² + (y + 2)² = 4
So, comparing (x+0)² + (y + 2)² = 4 with the
above equation of circle we get:
h = 0, k=-2 and r = 2 Therefore, center of the circle is (0, -2) and radius of the circle is r = 2.
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