Find the center and radius of the circle x2+y2-x+2y-3=0
Answers
Answered by
0
Step-by-step explanation:
given equation is x
2
+y
2
−x+2y−3=0
⇒ (x
2
−2×
2
1
×x+
4
1
)+(y
2
+2y+1)
⇒3+
4
1
+1
⇒(x−
2
1
)
2
+(y+1)
2
=
4
17
∴ the centre is (
2
1
,−1) and raius is
2
17
Answered by
0
Answer:
radius is 17 and 2 as per my calculation
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