Question

Find the center and the radius of the circle 2(x-3)^2+2y^2=8

Answer 1

2(x-3)2+ 2(y2)=8
divide the entire equation by 2,
we get
(x-3)^2+ y^2 =4

so from this it's clear that centre is (3,0) and radius is √4=2

Answer 2

Answer:

Step-by-step explanation:

Hello my very dear friend!!!!

Thanks for asking this question and contributing to the brainly!                        

Before going to the question let’s get some things to be cleared off!!      

Centre(c): (-g,-f)

Radius:  root over g^2+f^2-c

Therefore,

Opening the equation we get...

2(x-3)^2+2y^2=8

=>x2+y2-6x+5=0

Therefore centre..as given above is ;))

(3,0) ———>>>>equating....by 2gx..

Radius———

2....by equating...by above root g2+f2-c....

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Hope it helps you!!!

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Have a good day!!