Question

find the center of circle possing through A(-1,1),B(0,-4) AND C(-1,-5)​

Answer 1

Answer:

Step-by-step explanation:

Since the circle passes through all of the points, it is safe to say that the distances from the radius to the points are also equal.

Let the center be (x,y).

Therefore, RA=RB

(x+1)^2+(y-1)^2= (x-0)^2+(y+5)^2

x^2+2x+1 + y^2+1-2y= x^2 +  y^2+25+10y

2x-2y+2= 10y+25

2x-12y-23= 0

Similarly, RB= RC

(x-0)^2+(y+5)^2= (x+1)^2+(y+5)^2

x^2+y^2+25+10y= x^2+1+2x+y^2+25+10y

10y+25= 2x+26+10y

2x+1=0

x=-1/2.

Substitute x value in first equation.

2(-1/2)-12y-23=0

-1-33-12y=0

-34= 12y

y=-34/12

Therefore the center is (-1/2,-34/12)

Brainliest this answer, and follow anyone who does this much of work