Question

find the center of mass equletral triangle of masses 3kg,1kg,2kg seperated by distance 2cm
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Answer 1

Answer:

Explanation:

We then substitute the values as given from the situation:A⟶m1x1y1=1kg=0m=0mB⟶m2x2y2=2kg=1m=0mC⟶m3x3y3=3kg=12m=3–√2m

The values for point C are determined through trigonometery.

Putting these in the formula as follows:X=(1)(0)+(2)(1)+(3)(12)1+2+3=0+2+326=712Y=(1)(0)+(2)(0)+(3)(3–√2)1+2+3=0+0+33–√26=33−−√12

Thus, the centre of mass with respect to point A is situated at (712,33–√12)