Physics, asked by baba6460, 18 hours ago

Find the central angle of a sector whose area is 74.25 cm² and radius is 9 cm. (pi = 22/7​

Answers

Answered by vikkiain
1

Answer:

105°

Explanation:

area of sector = πr²Ø/360°

Given,

ar = 74.25cm² , r = 9cm

Now,

74.25 = (22/7)x9²Ø/360°

Ø = 74.25x360°x7/(22x9²)

Ø = 74.25x360°x7/(22x81) = 187110/1782

Ø = 105°.

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