Question

Find the central angle of the sector whose area is 462 cm² radius=21 cm​

Answer 1

Answer:

Answered by Guest on 2019-06-03 22:24:12 | Votes 9 | #

Area of sector = (θ/360°) × π r2, where r is the radius of circle

462 = (θ/360°) × (22/7) × (21)2

θ = 120°

Answer 2

Answer:

the central angle of the sector whose area is $462$ cm² and radius is $21$ cm is $120^0$

Step-by-step explanation:

Given:

The area is $462$ cm²

The radius is $21$ cm.

The area of a sector is $(\frac{\alpha }{360^0}).\pi .r^{2}$

By equating we get

$(\frac{\alpha }{360^0}).\pi .r^{2}=462\\\\(\frac{\alpha }{360^0})=\frac{462}{\pi .(21)^{2}} \\\\\alpha =\frac{360.462}{\pi .(21)^{2}} \\\\\alpha =120.048^0$