find the central angle of the sector whose radius is 10 cm and the length of the arc is 22 cm
Answers
Answered by
0
Answer:
Given that r=10.5cm and l=22cm.
360
∘
θ
×2πr=l
i.e.
360
∘
θ
×2×
7
22
×10.5=22
∴θ=22×360
∘
×
2
1
×
22
7
×
10.5
1
=120
Answered by
0
Answer:
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