Question

Find the centre & radius of circle for the equation :
x 2+ y2- 8x + 10y - 12 = 0​

Answer 1

Answer:

Centre: (4, -5)

Radius: 7.28 units

Step-by-step explanation:

Comparing with the equation of circle

${x}^{2} + {y}^{2} + 2gx + 2fy + c = 0$

Centre :(-g, -f) = (4, -5)

Radius :

${r}^{2} = {g}^{2} + {f}^{2} - c$

${r}^{2} = 16 + 25 - ( - 12) = 53$

$r = \sqrt{53} = 7.28 \: units$