Question

find the centre and radius of 2x^2 + 2y^2 - 3x + 2y - 1 = 0​

Answer 1

Step-by-step explanation:

$2 {x}^{2} + 2 {y}^{2} - 3x + 2y - 1 = 0 \\ {x}^{2} + {y}^{2} - \frac{3}{2}x + y - \frac{1}{2} = 0 \\ centre = ( \frac{3}{4} \frac{ - 1}{2})$

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