find the centre and radius of a circle 2x^2 +2y^2+4x-3y+5=0
Answers
Answer:
How can i find center and radius of the circle 2x2+2y2−2x+6y−15=0 ?
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The general form of circle is-
x^2+y^2+2gx+2fy+c=0
and formulas for calculating
centre= (-g,-f) and
radius=√(g^2+f^2-c)
So here, we first divide the whole equation by 2 to make the coefficient of x^2 and y^2 = 1
On dividing we get:
x^2+y^2-x+3y-15/2+0
On comparing with the general form of circle, we get:
g= -1/2 , f= 3/2 and c=-15/2
On applying the formulas,
centre = (1/2,-3/2)
radius = √{1/4+9/4-(-15/2)} =√{(10/4)+15/2} =√{(10+30)/4} = √40/4 =√10 =3.16 units.
Step-by-step explanation:
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