Question

Find the centre and radius of circle represented by
x² + y² + 6x - 4y + 4 = 0​

Answer 1

Answer:

(-3,2) center and 3 units radii

Step-by-step explanation:

Answer 2

Step-by-step explanation:

${x}^{2} + {y}^{2} + 6x - 4y + 4 = 0 \\ {x}^{2} + {y}^{2} + 6x - 4y = - 4 \\x + {y}^{2} + 6x - 4y = \sqrt{ - 4 } \\x + y + 6x - 4y = \sqrt{ - 2} \\x + y + x - y = \frac{ - 1.42}{24} \\ 2x = 0.05 \\x = 0.025$