Find the centre and radius of each of the circles whose equations 2x²+2y²- 3x + 2y-1 = 0
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Answered by
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Step-by-step explanation:
Tofindthecentreandradiusofcentre
2x
2
+2y
2
=3x−5y+7
2x
2
+2y
2
−3x+5y=7
x
2
+y
2
−
2
3
x+
2
5
y=
2
7
(
devided
by2
)
x
2
−
2
3
x+y
2
+
2
5
y=
2
7
x
2
−
2
3
x+
16
9
+y
2
+
2
5
y+
16
25
=
2
7
+
16
9
+
16
25
(x−
4
3
)
2
+(y+
4
5
)
2
=
2
7
+
16
9
+
16
25
=
2
7
+
16
34
=
16
90
⇒(x−
4
3
)
2
+(y+
4
5
)
2
=
16
90
Comparingwithgeneralequation
h=
4
3
,k=
4
−5
,r=
16
9
(h,k)=(
4
3
,
4
−5
)r=
4
90
Ans.
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