Question

Find the centre and radius of each of the following circles
2x^2 ±2y^2+3x+4y+9/8=0

Answer 1

Answer:

Radius = 1

Center a = -3/4   b =  -1

Step-by-step explanation:

Find the centre and radius of each of the following circles  

2x^2 ±2y^2+3x+4y+9/8=0

2x² + 2y² + 3x + 4y + 9/8=0

Dividing by 2

=> x² + y² + 3x/2 + 2y + 9/16 = 0

(x-a)² + (y-b)² = R²

where a & b are center of circle & R = radius

Adding (3/4)² & 1 ² both sides

=> x² + 3x/2 + (3/4)² + y² + 2y + 1² + 9/16 = (3/4)² + 1²

=> (x + 3/4)² + (y+1)² + 9/16 = 9/16 + 1²

Cancelling 9/16 from both sides

=> (x + 3/4)² + (y+1)²  =  1²

Radius = 1

Center a = -3/4   b =  -1