find the centre and radius of the circle 2 x^2 + 2y^ 2-x=0
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The General Equation of a circle in x-y plane is
(x-a) ^2 + (y-b) ^2 = R^2,
Where (a, b) is the center of the circle and R is it's radius.
Now, the given equation is 2(x) ^2 + 2(y) ^2 - x = 0.
I.e. x^2 + y^2 -x/2 =0.
I.e. x^2 - 2×(1/4)×x + 1/16 +y^2 = 1/16.
I.e. (x - 1/4)^2 + (y - 0)^2 = (1/4)^2.
Comparing this equation with general equation, we get,
Center is (1/4,0) and radius is 1/4 units.
That's it!!!
Enjoy with your circle!!!
Have fun bro!!!
(x-a) ^2 + (y-b) ^2 = R^2,
Where (a, b) is the center of the circle and R is it's radius.
Now, the given equation is 2(x) ^2 + 2(y) ^2 - x = 0.
I.e. x^2 + y^2 -x/2 =0.
I.e. x^2 - 2×(1/4)×x + 1/16 +y^2 = 1/16.
I.e. (x - 1/4)^2 + (y - 0)^2 = (1/4)^2.
Comparing this equation with general equation, we get,
Center is (1/4,0) and radius is 1/4 units.
That's it!!!
Enjoy with your circle!!!
Have fun bro!!!
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