Find the centre and radius of the circle
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2
it's centre is
(3,-2)
and radius is 5.
(3,-2)
and radius is 5.
yooseungho:
can you solve this problem
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Answered by
4
The eq of the circle is
x^2 + y^2 - 6x + 4y - 12 = 0
The general eq is
x^2+y^2 + 2gx + 2fy + c =0
Here
2g= -6
=> g= -3
2f= 4
=> f= 2
Center = (-g,-f)
= (3,-2)
Radius= √ (g^2+f^2 -c)
= √[(-3)^2 + (2)^2 -(-12)]
= √(9+4+12)
= √25
= 5 units
x^2 + y^2 - 6x + 4y - 12 = 0
The general eq is
x^2+y^2 + 2gx + 2fy + c =0
Here
2g= -6
=> g= -3
2f= 4
=> f= 2
Center = (-g,-f)
= (3,-2)
Radius= √ (g^2+f^2 -c)
= √[(-3)^2 + (2)^2 -(-12)]
= √(9+4+12)
= √25
= 5 units
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