Question

Find the centre and radius of the circle 2x^2+2y^2-8x+10y-11=D0​

Answer 1

Answer:

First equation =x2+y2+8x+10y−7=0

its centre =(−4,−5)

Second equation of the circle

=2x2+2y2+8x−12y−9=0

its, centre =(2,3)

radius:=r2(2+4)2+(3+5)2

r2=62+82=36+64

r2=100

r=10

The equation of the concentric 

circle =(x−2)2+(y−3)2=102

x2−4x+4+y2−6y+9−100=0

x2−4x+y2−6y+13−100=0

x

Answer 2

Answer:

2x ^ 2 + 2y ^ 2-8x + 10y-11 = D0 từ