Question

Find the centre and radius of the circle 3x^2+3y^2+4x-6y-4=0

Answer 1

Answer:

Step-by-step explanation:

firstly,compare the given equation with the standard form of circle

i.e x^2+y^2+2gx+2fy+c

we get

2g = 4 => g=2

2f = -6 => f=-3

c = -4.

we know that

centre =(-g,-f)

. `.center =(-2,3)

we know that

radius =√(g^2+f^2-c)

=√(2^2+(-3)^2-(-4))

=√17