Find the centre and radius of the circle 3x²+3y²-6x+4y-1
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Step-by-step explanation:
Show that the equation 3x
2
+3y
2
−6x+4y−1=0 represents a circle. Find its centre and radius.
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3x
2
+3y
2
−6x+4y−1=0⇒[(
3
x)
2
−2×
3
×
3
×x+(
3
)
2
]+[(
3
y)
2
+2×
3
×
3
2
y+(
3
2
)
2
]−3−
3
4
−1=0
⇒(
3
)
2
+(
3
y+
3
2
)
2
−
3
16
=0
3(x−1)
2
+3(y+
3
2
)
2
−
3
16
=0
(x−1)
2
+(y+
3
2
)
2
=
3×3
16
=(
3
4
)
2
center (1,
3
−2
) radius =
3
4
Answered by
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so dear here you use quadric Equation
a is not equal 0
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