Question

Find the centre and radius of the circle
(6
) x2 + y2 + 22 = 25, 2x + 3y + 2z = 9
.
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Answer 1

Answer:

so the center of the given circul is (h,k) = (0,0).

and the radius of given circul is √3.

Answer 2

Answer:

The center of the circle is $(0,0)$ and the radius of the circle is $\sqrt{3}$

Step-by-step explanation:

Given equation is

$x^2+y^2+22=25...(1) \\and \\2x+3y+2z=9...(2)$

Now we rewrite the equation $1$ as

$x^2+y^2=25-22\\x^2+y^2=3$

The above equation can also be written as

$(x-0)^2+(y-0)^2=(\sqrt{3})^2$

Now we compare it with general form of equation of circle that is

$(x-h)^2+(y-k)^2=r^2$

Therefore we get $(h,k)=(0,0)$ and $r=\sqrt{3}$

Hence, The center of the circle is $(0,0)$ and the radius of the circle is $\sqrt{3}$

Learn More:

Question: The center of a circle is on the line  $y=2x$ and the line $x=1$ is tangent to the circle at $(1,6)$.

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