find the centre and radius of the circle (x+2)² + (y-3)²=16
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The answer is D. Center (-2, 8) Radius = 4. This is because the x value in the equation is positive, which means it is negative on the graph, and the y value in the equation is negative, which means it is positive on the graph. The radius is the square root of what the equation equals, and the square root of 16 is 4. I hope this helps!
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in the equation (x+3)²+(y-2)²=16 the centre of the circle is
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