find the centre and radius of the circle x^2 +y^2 + 8x+10y - 8 = 0
Answers
Answered by
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Step-by-step explanation:
x^2 + 8x + 16 + y^2 +10y + 25 -8-16-25 = 0
(X+4) ^2 + ( y+5) ^2 = 49 = 7^2
so the centre is ( -4,-5) and radius is 7
by using formula ( x-a) ^2+ (y-b)^2 = r^2
Answered by
2
Answer:
the centre of the circle is ( -4 -5) and the radius of circle is 7
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