Question

Find the centre and radius of the circle x^2+y^2+8x-10y+8=0.​

Answer 1

Answer:

centre (-4,5)

Step-by-step explanation:

circle equation=x^2+y^2+2gx-2fy+c=0.(-g,-f)=centre

Your equation=x^2+y^2+8x-10y+8=0.

=x^2+y^2+2*4*x+2*(-5)*y+8=0.

it means in this equation g=4 and f=-5

centre=(-g,-f)=(-4,5)(Ans)

radius of the circle=√(g^2+f^2-c)

=√(4^2+(-5)^2-8)

=5.74(Ans)