Math, asked by annairwin, 2 days ago

Find the centre and radius of the circle
x² + y² – 8x + 12y – 3 = 0

need step by step explanation​

Answers

Answered by saswatmohapatra5a09
0

Answer:

Correct option is

A

(4,−5),53

Given   circle equation  

x2+y2−8x+10y−12=0here2g=−8∴g=−4and2f=10∴f=5∴centre(−g,−f)=(4,−5)radius=g2+f2−c=42+52−(−12)=16+25+12=53unit

Answered by amitnrw
0

Given : x² + y² – 8x + 12y – 3 = 0

To find : centre and radius of the circle

Solution:

x² + y² – 8x + 12y – 3 = 0

=> x² – 8x +  y² + 12y – 3 = 0

=>  x² – 8x + 16 - 16 +  y² + 12y +36 - 36 – 3 = 0

=> ( x - 4)²   + (y + 6)² = 55

=>  ( x - 4)²   + (y + 6)² = (√55)²

( x - h )²   + (y -k)² = (r)²

( h , k) is center and r is radius

center = (4 , - 6)  and radius = √55

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