Find the centre and radius of the circle
x² + y² – 8x + 12y – 3 = 0
need step by step explanation
Answers
Answered by
0
Answer:
Correct option is
A
(4,−5),53
Given circle equation
x2+y2−8x+10y−12=0here2g=−8∴g=−4and2f=10∴f=5∴centre(−g,−f)=(4,−5)radius=g2+f2−c=42+52−(−12)=16+25+12=53unit
Answered by
0
Given : x² + y² – 8x + 12y – 3 = 0
To find : centre and radius of the circle
Solution:
x² + y² – 8x + 12y – 3 = 0
=> x² – 8x + y² + 12y – 3 = 0
=> x² – 8x + 16 - 16 + y² + 12y +36 - 36 – 3 = 0
=> ( x - 4)² + (y + 6)² = 55
=> ( x - 4)² + (y + 6)² = (√55)²
( x - h )² + (y -k)² = (r)²
( h , k) is center and r is radius
center = (4 , - 6) and radius = √55
Learn More:
In the given fig AM,ANand BC fare tangents to the circle find the ...
brainly.in/question/9909143
In the figure o is the center of circle.radius of circle is 3.1cm and pa is ...
brainly.in/question/7157405
Similar questions