Question

find the centre and the radius of the circle 3x²+3y²-5x-6y+4=0​

Answer 1

Answer:

I don't know the answer sorry

Answer 2

Step-by-step explanation:

Given equation is 3x

2

+3y

2

−5x−6y+4=0

Divide throughout by 3

⇒x

2

+y

2

−

3

5

x−2y+

3

4

=0

Now comparing above equation with general equation of circle, x

2

+y

2

+2gx+2fy+c=0

Centre of the circle is (−g,−f)=(

6

5

,1)

and radius =

g

2

+f

2

−c

=

36

25

+1−

3

4

=

6

13