find the Centre of a circle passing through the points (6,-6), (3,-7), and (3,3).
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Answered by
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if these points form centre.......then it forms a triangle inscribed in that circle....
let the points be A,B,and C.
here A (x1,y1)=(6,-6)
B (x2,y2)=(3,-7)
C(x3,y3)=(3,3)
the given points forms an isoceles triangle.
since....we know that centre of a circle is cenroid of the triangle in which it is inscribed in the cirle.
centroid of a triangle =(x1+x2+x3/3,y1+y2+y3/3)
here cenroid of given triangle =6+3+3/3,-6+(-7)+3/3)
=(12/3,-10/3)
=(4,-3.3)
therefore ..(4,-3.3) is the centre of that circle
let the points be A,B,and C.
here A (x1,y1)=(6,-6)
B (x2,y2)=(3,-7)
C(x3,y3)=(3,3)
the given points forms an isoceles triangle.
since....we know that centre of a circle is cenroid of the triangle in which it is inscribed in the cirle.
centroid of a triangle =(x1+x2+x3/3,y1+y2+y3/3)
here cenroid of given triangle =6+3+3/3,-6+(-7)+3/3)
=(12/3,-10/3)
=(4,-3.3)
therefore ..(4,-3.3) is the centre of that circle
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shaun5:
may the answer be right or wrong.....if it is wrong please excuse me....i will see not to repeat it again
Answered by
10
hope the answer is correct
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