find the centre of a circle passing through the points (6,-6), (3,-7)&(3,3)
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Answer:(3,-2) is the centre
Step-by-step explanation:let the centre of the circle be (x,y)
Since it is a circle all the points on the circle must be equidistant from the centre
Therefore the square of their distances is the same
(x-6)²+(x+6)²=(x-3)²+(x+7)²
By solving we get
6x+2y=14. ⇒(1)
And
(x-3)²+(y+7)²=(x-3)²+(y-3)²
By solving this we get
y=-2
Substituting this is the equation(1) we get
6x+2(-2)=14
6x=14+4
6x=18
x=3
Therefore the centre of the circle is (x,y)≡(3,-2)
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