Question

find the centre of gravity of a
100 mm x 150 mm x 30mm.
T-section​

Answer 1

Answer:

4,50,000

Step-by-step explanation:

100×30×150

4,50,000

Answer 2

Answer:

Step-by-step explanation:

Given: Dimension of T-section is 100 mm × 150 mm × 30mm.

First find the centre of the horizontal piece A, a rectangle, with side horizontal length a= 100, and vertical w= 30. This is 15mm from the top and 75mm from either side. Area of A is 100*30 = 3000 mm²

Next find the centre of the vertical piece minus the overlapping portion of the upper piece. This piece B is a square of dimensions 30mm. The centre is located 25mm from the bottom and 15mm from either side. Area of B is 30*30 = 900 mm²

Last is to use a formula to calculate by graphic method. Set the bottom of T sit on the x-axis and the left side of T touch the y-axis. y is the measure of height of T and the centre of gravity is along the line vertically dividing T.

A is A₁ =3000, y₁ is height of T-25 = 85

B is A₂ = 900, y₂ is 15.

The centre of gravity y꜀ = (A₁ y₁ +A₂ y₂)/(A₁ +A₂) = (3000*85+900*15)/(3000+900)= 268500/3900=68.84mm from x axis at x= 85mm.

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