Question

find the centre of mass of 3 particles at the vertices of an equilateral triangle masses of particles are 100g, 150g, 200g. each side of equilateral triangle is 0.5 m

Answer 1

hey mate,
your answer is in the attachment

Answer 2

Ans:-

Given that mass of the body as

   m1= 100g

   m2= 150g

   m3= 200g

 Side of triangle (a) = 0.5m =50cm

By using center of mass concept along both axis

    for x-axis:-

     Xcm = m1x1 + m2x2 + m3x3

                      m1 + m2 + m3

    Xcm =  0×100+150×50+200×25

​                          100+150+200

    Xcm =   0+7500+5000

                          450

      Xcm = 27.8cm = 0.278m

now , for y-axis:

       Ycm = m1y1 + m2y2 + m3y3

                        m1+m2+m3

        Ycm = 0×100+0×150+$\sqrt{3}$×25×200

                               450

         Ycm = 19.2cm = 0.192m