Find the centre of mass of a uniform disc of radius 'a' from which a circular section of radius 'b' has been removed . The centre of the hole is at a distance c from the centre of the disc
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Answer: The centre of mass of a uniform disc of radius 'a' from which a circular section of radius 'b' has been removed is (Mc/ M-m)
Explanation:
We consconsider the mass of the disc at the centre on the general term.
Now, the circular section of radius 'b' has been removed so a hollow space is created at c-b distance from disc's centre. Therefore, Oo'=C and -m is at o'.
Let distance of X is CM then
X= ((M×0) -(m×c)) /M-m
X= (Mc/ M-m)
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