Find the centre of the circle passing through (6, -6), (3, -7) and (3, 3).
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3) 2 A Find the centre of the circle passing through (6, -6), (3, -7) and (3, 3).
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Centre is (6,-2)
Step-by-step explanation:
Let A(6, -6), B(3, -7) and C(3, 3) be the points on the circle. Let P(x, y) be the centre and PA, PB and PC be its radii.
PA = PB = PC
PA² = PB² = PC²
(x-6)² + (y+6)² = (x-3)² + (y+7)²
x² + 36 - 12x + y² + 36 +12y = x² + 9 - 6x + y² + 49 + 14y
6x + 2y = 14 -------------(1)
Also, (x-3)² + (y+7)² = (x-3)² + (y-3)²
x² + 9 - 6x + y² + 49 + 14y = x² + 9 -6x + y² - 6y + 9
20y = -40
Therefore y = -2
Substituting in (1), we get: 6x - 4 = 14
x = 18/3 = 6
So the coordinates of the centre are P(6,-2)
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