find the centre of the circle passing through the point (6 -6) (3 -7) (3 3)
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Step-by-step explanation:
we have to calculate the work done on charge 1 C in an electrostatic field 2 N/C along x - axis when charge is moved through a distance 2.5 m along +x axis.
solution : we know force, F = qE
where q is charge and E is electrostatic field.
here q = 1 C and E = 2 N/C along x - axis
so the force along x - axis , F = 1 C × 2N /C = 2 N
displacement along x - axis , s = 2.5 m
work done = force × displacement along force
= 2 N × 2.5 m
= 5 Nm = 5J
Therefore the workdone on the charge 1 C in an electrostatic field 2 N/C along x - axis is 5 J
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