find the centre of the circle passing through the points (6,-6)(3,-7)(3,3)
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(3,-7) (3,3)
x = 3
as, -7 + 3 = 10
c = 5
(x-3)² + (y+b)²= 5²
b = 2
so,
(x-3)² + (y+2)²= 5²
diameter of circle= 10 (7+3)
radius= 5
center= (3, -2)
as we know
-7+5=-2 and 3-5=-2
(x-3)²+(y+2)² = 25
x = 3
as, -7 + 3 = 10
c = 5
(x-3)² + (y+b)²= 5²
b = 2
so,
(x-3)² + (y+2)²= 5²
diameter of circle= 10 (7+3)
radius= 5
center= (3, -2)
as we know
-7+5=-2 and 3-5=-2
(x-3)²+(y+2)² = 25
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