Question

find the centre of the circle whose two end points of its diameter are (3,2),(-9,-11).

Answer 1

Answer:

Answer

Centre of first circle

x

2

+y

2

+16x−14y−1=0.

is(−g,−f)

⇒(−8,7)→P

ForIICircle:

Centre→(2,−5)→Q

EquationofcirclewithP&Qasdiametricendpoints:

Centre→(

2

−8+2

,

2

7−5

)

⇒(−3,1).

radius=

2

1

(2+8)

2

+(−5−7)

2

=

2

1

100+144

=

2

244

.

⇒(x+3)

2

+(y−1)

2

=

4

244

⇒(x+3)

2

+(y−1)

2

=61

Ans.

Step-by-step explanation:

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Answer 2

Answer:

0,0

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