find the centriod of the triangle whose vertices are (4,-3),(-9,7) and(3,13)
Answers
Answered by
0
Answer:
Let the ΔABC with vertices A=(x1,y1)=(4,−8),B=(x2,y2) =(−9,7)
and C=(x3,y3)=(8,13)
∴ its centroid G=(x1+x2+x3)/,(y1+y2+y3)/3=(4−9+8)/3−(8+7+13) /3
∴G=(1,4)
Similar questions