Question

find the centriod of trianglePQR whose vertices are p(1,1) Q(2,2) R(-3,-3)​

Answer 1

Answer:

G = (0,0)

Step-by-step explanation:

coordinates of centroid are given by (x1+x2+x3/3 , y1+y2+y3/3)

here x1 = 1 y1 = 1

x2 = 2 y2 = 2

x3 = -3 y2 = -3

G = (1+2-3/3 , 1+2-3/3)

G = (0,0)