Question

Find the centripetal acceleration of person located at earth's equator with respect to earth's rotational axis. Earth's radius approximately 6.4 x 10⁶m. Express your answer in m/s​

Answer 1

Answer:

Here is your answer .

Explanation:

Answer 2

Answer:

The centripetal acceleration is $0.0338ms^{-2}$

Explanation:

On the equator, a point rotates in a circle of radius $R=6.4*10^6m$

The angular velocity of rotation is ω$=\frac{2}{1 day}$ π

ω $=\frac{2*\frac{22}{7} }{24*60*60s}$

$=7.27*10^{-5}s^{-1}$

Thus, the centripetal acceleration is :

ω²R$=(7.27*10^{-5}s^{-1})^2*6.4*10^6m$

$=0.0338ms^{-2}$

Centripetal acceleration :

The characteristic of an object's motion when it travels along a circular path is known as centripetal acceleration.

Centripetal acceleration applies to any item traveling in a circle with an acceleration vector pointing in the direction of the circle's centre.