Find the centrode of a triangle formed by the lines represented by x=2y, 2x+y=0, 3x-y=5
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Given : triangle formed by the lines represented by
x=2y ,
2x+y=0,
3x-y =5
To Find : centroid of triangle
Solution:
x=2y , 2x+y=0,
=> 2(2y) + y = 0 => 5y = 0 => y = 0
x = 0
(0,0 )
2x+y=0, 3x-y =5
=> 5x = 5 => x = 1
y = - 2
( 1 , - 2)
x=2y 3x-y =5
=> 6y - y = 5 => y = 1
x = 2
(2 , 1)
Vertex of triangle
(0,0 ) , ( 1 , - 2) , (2 , 1)
Centroid = (0 + 1 + 2)/3 , ( 0 - 2 + 1)/3
= 1 ,-1/3
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