Math, asked by obaidcool34, 1 month ago

Find the centroid and area of the triangle formed by the lines 3x2

- 4xy + y2

= 0, 2x - y = 6.​

Answers

Answered by amitnrw
9

Given : triangle formed by the lines 3x² - 4xy + y² = 0, 2x - y = 6.​

To Find :centroid and area of the triangle

Solution:

3x² - 4xy  + y² =0

=> 3x² - 3xy - xy + y² = 0

=> 3x(x - y)  - y(x - y ) = 0

=> (3x - y)(x - y) = 0

=>  3x - y = 0

    x - y = 0

3x - y = 0    ,    x - y = 0

=> (0 , 0)

3x - y = 0    ,     2x - y = 6.​

=> ( - 6 , -18 )

x - y = 0  ,  2x - y = 6.​

=> ( 6 , 6)

(0 , 0) ,  ( - 6 , -18 ) ,  ( 6 , 6)

Centroid  =  ( 0 - 6 + 6)/3 , ( 0 - 18  + 6)/3

= ( 0 , - 4)

Area of triangle

= (1/2) |  0 (-18 - 6) + 6(0 - 6)  + 6(0 - (-18)) |

= (1/2) | 0  - 36 + 108 |

= (1/2) | 72 |

= 36

Area of triangle = 36  sq units

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