find the centroid of a ∆ABC ,whose vertics are A(-1,0),B(7,1)&(3,5)
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Answered by
0
Answer:
answer is 3,2
Step-by-step explanation:
hope you understand
Answered by
2
Given that
A(-1, 0)
B=(7, 1)
C=(3, 5)
Centroid of triangle ABC=(X1+X2+X3/3, Y1+Y2+Y3/3)
That is equal to (-1+7+3+/3,0+1+5/3)
=(9/3, 6/3)
=(3,2)
Hence (3, 2) is the centroid of triangle with vertices A(-1, 0), B=(7, 1), C=(3, 5)
HOPE IT HELPS YOU DEAR..........
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