Question

find the centroid of a angle PQR,whose vertices are p(1,1), Q(2,2) R(-3,-3).​

Answer 1

Use the centroid formula

G=(x1 +x2+x3 /3, y1+y2+y3/3)




The answer will be (0,0)

Answer 2

x1=1 x2=2 x3=-3

y1=1 y2=2 y3=-3

let the coordinates of centroid G be (x,y)

By Centroid formula,

x = x1+x2+x3/3

= 1 + 2 -3/3

= 0/3

=0

y= y1+y2+y3/3

= 1 + 2 -3

=0

therfore co - ordinates of centroid

G(x,y)=G(0,0)

personally i think there is something wrong with ur question bcuz how can both cordinates be zero