Find the centroid of a loop of the lemniscate l square equals to a square cos 2 theta
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I have to find the arc length of a lemniscate with polar equation r=2(cos(2θ))1/2.
So far I got like 4cos(2θ)+(−2sin(2θ)cos(2θ)√)−−−−−−−−−−−−−−−−−−−−√.
I don't know how to proceed, I can't seem to figure out how to approach this.
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